Chemistry
aliwheeler
1

1. What is the empirical formula for a compound containing 63.8% N and 36.2% O? a. N₂O₅ b. N₂O₃ c. NO₂ d. NO e. N2₂O

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Browneyes

[latex]M\ N_2=28g/mol\\ 63,8\%--28g\\ 100\%--x\\ x=43,89g[/latex] 43,89g≈44g 44g == 2x 14g (N) + 1x 16x(O) M N₂O = 44g

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