2.15 g of an unknown gas at 71 degrees C and 1.10 atm is stored in a 1.75 L flask. Solve for the density and the molar mass of the gas.

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(1) Answers

Peanut2

For this we use the ideal gas equation for the calculations. It is expressed as:
PV = nRT
Density = m/V
Density = 2.15 g / 1750 mL = 0.00123 g/mL
Since,
PV = nRT
P = nRT/V
P = density RT / Molar mass
Thus,
Molar mass = densityRT / P
Molar Mass =(1.23 )(0.08206)(71+273.15) / 1.10 = 31.58 g/mol