Chemistry
KyaG
26

5.00 mol of gas occupy a volume of 112 L at a pressure of 1.00 atm. What is the kelvin temperature of the gas?

+2
(1) Answers
Themac4ever

n = 5 moles, V = 112 L, P = 1.00 atm PV = nRT --> T = PV/nR T = (1)(112) / (5)(.0821) T = 272.8 K = 273 K

Add answer