Mathematics
coreyhumble76
18

A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, how long until the ball hits the ground?

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(1) Answers
mcguirem141

[latex]h=-16t^2+60t+5[/latex] The ball will hit the ground when [latex]h=0[/latex]: [latex]-16t^2+60t+5=0[/latex] [latex]D=b^2-4ac=60^2-4*(-16)*5=3600+320=3920[/latex] [latex]t=\frac{-b-\sqrt{D}}{2a}=\frac{-60-\sqrt{3920}}{-32}=\frac{-60-62.61}{-32}\approx 3.8[/latex]

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