Mathematics
cecy43219
24

A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h = -16t^2 + 48t + 6. How long does it take the ball to reach its maximum height? What is the ball's maximum height?

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(1) Answers
tyarianna22

so you have to find the velocity (or first derivative) from the position function of h=-16t^2+48t+6 the velocity is -32t+48 which you then have to set equal to 0 in order to find t -32t+48=0 -32t=-48 t=1.5 you then take your t value and sub it back into your original position function -16(1.5)^2+48(1.5)+6 which will give you a maximum height of 42 feet so the time it takes is 1.5 seconds to reach a maximum height of 42 feet

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