A collection od dimes and quarters totals $9.90. There are six more quarters than dimes. How many of each coin are there?

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(1) Answers

longhornlova12

We do as follows:
let x = number of quarters
y = number of dimes
We have two unknowns. We need two equations to solve this.
.25x + .10y = 9.90
x = y + 6
x =30 quarters
y = 24 dimes
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