Mathematics
Anisa00
1

A garden is in the shape of a rectangle and has a perimeter of 58 yards. The length of the garden is 5 more than twice the width. Find the dimensions of the garden.

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(1) Answers
nevar

The perimeter will equal 2(L) + 2(w), so what's the length and width? Well it says the length is 5 more (+5) than twice the width (2w)... so L = 2w+5 Since we know the perimeter and the length, we can find the width. p = 2(L) + 2(w) 58 = 2(2w+5) + 2w 58 = 4w + 10 + 2w 58 = 6w + 10 48 = 6w 48/6 = W 8 = W Now that we have an integer for w, we can substitute it back into the equation and solve for L. p = 2(L) + 2(w) 58 = 2L + 2(8) 58 = 2L + 16 42 = 2L 42/2 = L 21 = L So the dimensions of the garden are Length = 21 yards Width = 8 yards

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