A gas has an initial volume of 21.7 L at a pressure of 0.4 atm and a temperature of 252 K. The pressure of the gas increases to 2 atm as the temperature increases to 323 K. What is the final volume of the gas?

(2) Answers

According to the combined gas law: (P₁*V₁)/T₁=(P₂*V₂)/T₂, where P is the pressure, V is the volume and T is the temperature. P₁=0.4 atm = 40530 Pa V₁=21.7 L = 0.0217 m³ T₁=252 K P₂=2 atm = 202650 Pa T₂=323 K V₂=? We need to solve for V₂: (P₁*V₁)/T₁=(P₂*V₂)/T₂ (T₂*P₁*V₁)/T₁=P₂*V₂ (T₂*P₁*V₁)/(T₁*P₂)=V₂, now we plug in the numbers and get: V₂=0.00556 m³, and we can see that with increased temperature and pressure the volume V₂ has decreased.  When we transfer V₂=0.00556 m³ to liters we get that 0.00556 m³=5.56 L. That can be rounded up to V₂=5.6 L.


theeeeeeeeeeeeeeeee answer is 5.6 L

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