A laboratory designed a radio telescope with a diameter of 320 feet and a maximum depth of 46 feet. Points on graph are: (-160,46),(160,46). Find the equation of this parabola.

 the shape of the telescope is said to be a parabola. In this case, the general form which we will pattern our equation is  y- k= 4a(x – h)^2    (h,k) or vertex = (0,0)  y = 4ax^2 We substitute x = 320/2 = 160, y = 46  46 = 4a (160)^2  46 = 4a (25600)  4a = 23/12800  hence the equation is y = (23/12800)x^2