Physics
Weader350
13

A mixer-grinder has an efficiency of 65 percent. If the output work is 50 joules, what is the amount of input work required?

+1
(1) Answers
Mackensie

We are to look for the input work that would yield 50 J when it is only at 65% efficiency. To show this mathematically: Input work  x (65/100) = 50 J. So to find the input work, we are to divide 50 J by (65/100). This is shown below: Input work = 50 / (65/100) = 76.92 J Therefore, the input work needed is 76.92 J.

Add answer