A mixer-grinder has an efficiency of 65 percent. If the output work is 50 joules, what is the amount of input work required?
We are to look for the input work that would yield 50 J when it is only at 65% efficiency. To show this mathematically: Input work x (65/100) = 50 J. So to find the input work, we are to divide 50 J by (65/100). This is shown below: Input work = 50 / (65/100) = 76.92 J Therefore, the input work needed is 76.92 J.