Alex made a sketch for a homemade soccer goal he plans to build. The goal will be in the shape of a triangular prism. The legs of the right triangles at the sides of his goal measure 4 ft and 8 ft, and the openin along the front is 24 ft. How much space is contained within this goal

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To do this you need to fill in the equation: 1/2(height) * side length * width. So, height = 8 ft, side length = 4 ft, and width = 24 ft. So, plugging in the numbers you get: 1/2(8)*4*24 = 4*4*24 = 384 ft   Hope this helped!

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