EdHojeij
4

# An aircraft has a liftoff speed of 33 m/s. what minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240m? show work.

We will use simple formula for velocity with constant acceleration. $v=v0+at$ and formula for path $x=x0+v0t+ \frac{1}{2}a t^{2}$ where: v0 - initial velocity a - constant acceleration t- time x - path x0 - initial position v0, and x0 are equal to 0 in this case, so we can simplify our formula to $v=at$ and $x= \frac{1}{2}a t^{2}$ We can modify first formula to get time $t= \frac{v}{a}$ and substitute it to second formula. $x= \frac{1}{2}*a \frac{ v^{2}}{ a^{2} } = \frac{1}{2} \frac{ v^{2} }{a}$  Now we can find acceleration $a= \frac{1}{2} \frac{ v^{2} }{x} =2.27$ m/s