An aircraft has a liftoff speed of 33 m/s. what minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240m? show work.

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We will use simple formula for velocity with constant acceleration. [latex]v=v0+at[/latex] and formula for path [latex]x=x0+v0t+ \frac{1}{2}a t^{2} [/latex] where: v0 - initial velocity a - constant acceleration t- time x - path x0 - initial position v0, and x0 are equal to 0 in this case, so we can simplify our formula to [latex]v=at[/latex] and [latex]x= \frac{1}{2}a t^{2} [/latex] We can modify first formula to get time [latex]t= \frac{v}{a} [/latex] and substitute it to second formula. [latex]x= \frac{1}{2}*a \frac{ v^{2}}{ a^{2} } = \frac{1}{2} \frac{ v^{2} }{a} [/latex]  Now we can find acceleration [latex]a= \frac{1}{2} \frac{ v^{2} }{x} =2.27[/latex] m/s 

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