An object is thrown in the air with an initial velocity of 5 m/s from a height of 9 m. The equation h(t) = –4.9t2 + 5t + 9 models the height of the object in meters after t seconds. About how many seconds does it take for the object to hit the ground? Round your answer to the nearest hundredth of a second. Question 11 options: 0.94 seconds 1.50 seconds 2.00 seconds 9.00 seconds

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After being thrown, the object would take about 2 seconds to hit the ground. We can find this by looking at the second x-intercept, which is where the graphed equation crosses the line on the right.

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