Physics
bricktoria13
27

An object is thrown upward with a speed of 14 m/s on the surface of planet X where the acceleration due to gravity is 3.5 m/s2. How long, in seconds, does it take for the object to reach the maximum height?

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(2) Answers
iza90290

u = 14 m/s, g = 3.5 m/s². At maximum height, v = 0 v = u - gt 0 = 14 - 3.5t 3.5t = 14 t = 14/3.5 t = 4 time = 4 seconds

ElizbethLiddle208

The maximum height of the object is where the final velocity becomes zero. The final velocity is obtained by,                                   Vf = V1 - gt Substituting the known values,                                    0 = 14 m/s - (3.5 m/s²)t The value of t is 4 seconds. 

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