Mathematics
sammy305
14

Becky wants to fence in a rectangular play area for her dog. If she was 82 feet of fencing and wants the length of the play area to be 9 feet longer than its width then what should the dimensions of the play area be?

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(2) Answers
taliyahbrown112

length= width+9    ----- Now we can substitute length with width! Perimeter = 2(length) + 2(width) Perimeter = 82 82= 2(w+9) + 2w 41 = w+ 9 + w 41-9 = 2w 32 = 2w 16= w    (now plug w into the equation for length) length = 16 + 9 = 25 SOO... Dimensions = 16 x 25

Jayda

ok fencing=perimiter perimiter=L+L+W+W=2L+2W=2(L+W) 82=2(L+W) divid eboth sides by 2 for ease of use 41=L+W if she wants legnth to be 9 more than width, then L=9+W subsitute 9+W for L 41=9+W+W 41=9+2W subtract 9 32=2W divide 2 16=W subsitute L=9+W L=9+16 L=25 the pen should be 25 feet by 16 feet

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