The first one is 36/25 which is B . The second one is 5/2 which is C.

[latex]1. \ \ \left(\frac{7*3*2}{7*5}\right)^2* \left(\frac{7^0}{5^{-3}}\right)^3*5^{-9}= \frac{3^2*2^2}{5^2}* \left(5^{3}}\right)^3*5^{-9}= \frac{36}{25} *5^9*5^{-9} = \\ \\ \frac{36}{25}*5^0 = \frac{36}{25} \\ \\ \\2. \ \ \ \frac{5^{-3}*2^2*5^6}{2^3*5^2}=\frac{5^6}{5^3*2*5^2}= \frac{5^6}{2*5^5} = \frac{5}{2} [/latex]