Eyjafjallajökull is a Volcano in Ice land. During a recent eruption, the volcano, spewed out copious amounts of ash. One small was ejected from the volcano with an initial velocity of 368ft/sec. The height H, in feet, of our ash projectile is given by the equation H= -16t +368t 1. When does the ash projectile reach its maximum height? 2. What is its maximum height? 3. When does the ash projectile return to the ground?
(1) Answers
1. The maximum height is at H` ( t ) = 0 H` ( t ) = ( -16 t² + 368 t )` = - 32 t + 368 - 35 t + 368 = 0 35 t = 368 t = 368 : 32 t = 11.5 sec. 2. H max = - 16 · 11.5² + 368 · 11.5 = - 2,116 + 4.232 H max = 2,116 ft 3. It returns to the ground after: t = 2 · 11.5 = 23 seconds.
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