Mathematics
Zola109
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Factor Completely: 2x2 − 18 Prime 2(x2 − 9) 2(x + 3)(x − 3) 2(x + 3)(x + 3)

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longhornlova12

To factor the given function, find a term that is divisible by both terms. For this problem, the factor would be 2, since 2x^2 and -18 are both divisible by 2. 2(x^2 - 9) You could further factor out x^2 - 9 because it is factorable by (x - 3) and (x + 3). Thus, it would be 2(x -3)(x+3)

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