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# Find lim f(x), x->3- Can you please explain this. I dont know why but this is confusing me.

Hello, $\lim_{x \to 3-} f(x)=1\ \ is\ since ( x\ \in\ Dom(f)\ and\ \forall\ \delta\ \textgreater\ 0 \ and\$ $( x \in \ Dom( f ) \ and \ 3-\delta \ \le \ x \ \ \textless \ p ) == \textgreater \ 1 - \epsilon \ \le\ f ( x )\ \le \ 1 + \epsilon \$ $\lim_{x \to 3+} f(x)=3$ $f(3)=7\\ \lim_{x \to 3} f(x) \ does\ not\ exist.$