Mathematics
PinkkBaby
14

find the sine, cosine, and tangent of 45 degrees. a. sin 45 degrees = negative square root of 2 divided by 2, cos 45 degrees = negative square root of 2 divided by 2, tan 45 degrees = negative square root of 2 b.sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = square root of 2 c. sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = 1 d.sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = −1

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(1) Answers
nikolak

[latex]sin(45) = \frac{\sqrt{2}}{2}[/latex] [latex]cos(45) = \frac{\sqrt{2}}{2}[/latex] [latex]tan(45) = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1[/latex] The answer is C.

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