# How many combinations of 3 students can a teacher choose from 32 students? A. 96 B. 4960 C. 29,760 D. 32,768

(2) Answers

[latex]{32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960[/latex]

Add answer

Sign in
Sign up

(2) Answers

[latex]{32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960[/latex]

Add answer

Sign in
Sign up