Chemistry
NYCDEE
10

How many mL of 4.0% Mg(NO3)2 solution would contain 1.2 g of magnesium nitrate?

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(1) Answers
NealPomainville958

4.0 % in mass per volume : 4.0 g ---------- 100 mL 1.2 g ----------  ( volume ) Volume =  1.2 x 100 / 4.0 Volume = 120 / 4.0 = 30 mL hope this helps!

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