Mathematics
laurenmabe2001
7

How to Simplify 243^1.2

+0
(1) Answers
lyssie11234

[latex]243^{1,2}=243^{1\frac{2}{10}}=243^{1\frac{1}{5}}=243^{1+\frac{1}{5}}=243^1\cdot243^\frac{1}{5}=243\sqrt[5]{243}\\\\=243\sqrt[5]{3^5}=243\cdot3=729[/latex]

Add answer