How to solve: y^2 +10y -264=0
It says: solve to obtain y=12 and y= -22
but i don't know how to get this answer

+0

(1) Answers

Skyheart

Calculate [latex]\Delta=b^2-4ac=10^2-4*1*(-264)=100+1156=1256[/latex]
Then, the solutions are:
[latex]y_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-10-\sqrt{1256}}{2} \\ y_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-10+\sqrt{1256}}{2}[/latex]
Do the calculations and you're done.