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# How to solve: y^2 +10y -264=0  It says: solve to obtain y=12 and y= -22  but i don't know how to get this answer

Calculate $\Delta=b^2-4ac=10^2-4*1*(-264)=100+1156=1256$ Then, the solutions are: $y_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-10-\sqrt{1256}}{2} \\ y_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-10+\sqrt{1256}}{2}$ Do the calculations and you're done.