Mathematics
veralystic
8

How to solve: y^2 +10y -264=0  It says: solve to obtain y=12 and y= -22  but i don't know how to get this answer

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(1) Answers
Skyheart

Calculate [latex]\Delta=b^2-4ac=10^2-4*1*(-264)=100+1156=1256[/latex] Then, the solutions are: [latex]y_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-10-\sqrt{1256}}{2} \\ y_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-10+\sqrt{1256}}{2}[/latex] Do the calculations and you're done.

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