Mathematics
madda
5

i dont know how to do this someone please help 3 (y2+7)=48

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(2) Answers
Gracie216

[latex]3 (y^2+7)=48 \\ \\ 3y^2+21-48 =0 \\ \\3y^2-27 =0\ \ /:3\\ \\y^2-9=0\\ \\ y^2-3^2=0 \\ \\(y-3)(y+3)=0\\ \\y-3=0 \ \ or \ \ y+3=0 \\ \\y=3 \ \ or \ \ y=-3 \\ \\ \\ a^2-b^2 =(a-b)(a+b) [/latex]

jcampos

3y^2 + 21=48 -21 -21 3y^2=27 ÷3 ÷3 y^2=9 sqrt. sqrt. y=3

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