Mathematics
petershongwe
16

Identify the outlier in the following list. Then find the mean and median of the list with and without the outlier. 10, 4, 20, 5, 11, 150, 7 a. Outlier = 10 Mean with outlier = 29.6 Median with outlier = 10 Mean without outlier = 44.1 Median without outlier = 10.5 c. Outlier = 150 Mean with outlier = 9.5 Median with outlier = 8.5 Mean without outlier = 29.6 Median without outlier = 10 b. Outlier = 10 Mean with outlier = 10 Median with outlier = 29.6 Mean without outlier = 8.5 Median without outlier = 9.5 d. Outlier = 150 Mean with outlier = 29.6 Median with outlier = 10 Mean without outlier = 9.5 Median without outlier = 8.5

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(2) Answers
RasheedaLaudermilk

Outlier: 10 Mean with outlier: 29.6 Median with outlier: 10 Mean without outlier: 9.5 Median without outlier: 8.5

Clapearl

Answer:  d. Outlier = 150 Mean with outlier = 29.6 Median with outlier = 10 Mean without outlier = 9.5 Median without outlier = 8.5 Outlier: 150 The value in the data set that is far greater or less than most of the other values in the data set. Mean w/ Outlier: 29.6 4 + 5 + 7 + 10 + 11 + 20 + 150 = 207 207 / 7 = 29.6 Median w/ Outlier: 10 The 4th value out of the 7 total in the data set, 10; it is the median because it is the middle-most value in the data set. Mean w/o Outlier: 9.5 4 + 5 + 7 + 10 + 11 + 20 = 57 57 / 6 = 9.5 Median w/o Outlier: 8.5 When there are two middle-most values in a data set, add them together and divide by to ( average them ) to get the median. 7 + 10 = 17 17 / 2 = 8.5

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