Mathematics
neennyne
17

If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?

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YolandeSehl667

i  Acehello : let : A(-6,6)  B(6,-2) the center is w((-6+6)/2 , (6-2)/2)....(midel [ AB] w(0 ,2) the ridus is : r = AB/2 AB = √(-6-6)²+(6+2)² = √(144+64) =√208/2 an equation in standard form equation of the circle : (x+0)²+(y-2)² =  (√208/2)²=208/4 = 52

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