Mathematics
charl99
5

In an examination there are four multiple choice questions with 3 options each, of which one option is the correct answer. In how many ways can a student answer, such that he fails to answer all the four questions correctly? Thank you for help :)

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(1) Answers
shaun1

4 multiple choice questions 3 answers per question 4 × 3 = 12 12 possible answers total 12 - 4 = 8 8 incorrect answers 4 correct answers 3 × 3 × 3 × 3 = 81 81 possible ways they can answer Only one of those ways is 100% correct. 81 - 1 = 80 80 ways

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