1/2 because 8x2= 16 but 9 is only one higher than 8

[latex]\frac{9}{16}-0=\frac{9}{16}\\\\\frac{9}{16}-\frac{1}{2}=\frac{9}{16}-\frac{8}{16}=\frac{1}{16}\\\\2-\frac{9}{16}=\frac{32}{16}-\frac{9}{16}=\frac{23}{16}\\\\\frac{1}{16} < \frac{9}{16} < \frac{23}{16}\\\\Answer:Is\ \frac{9}{16}\ close\ to\ \frac{1}{2}.[/latex]