LenaSmith
11

# It takes 54.0J to raise the temperature of an 8.80g piece of unknown metal from 13.0∘C to 24.8∘C. What is the specific heat for the metal?

$Formula\ for\ thermal\ capacity:\\\\Q=cm \Delta T\\\\ Q-heat\\c-specific\ heat\\m-mass\\ \Delta T-change\ in \ temparature\\\\Q=54J\\m=8,8g\\ \Delta T=24,8-13=11,8^{\circ}C \\\\c=\frac{Q}{m \Delta T}=\frac{54}{8,8*11,8}=0,52\frac{J}{g*^{\circ}C}\\\\Answer\ is\ c=0,52\frac{J}{g*^{\circ}C}.$