Mathematics
Reeve404
15

One positive number is the square of another positive number. their sum is 132. find the numbers.

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(1) Answers
lhaelha2

x +x²= 132 x +x²-132= 132-132 x²+x -132 = 0 (x-11) (x+12) = 0 x-11 = 0 X+12=0 x-11+11 = 0+11 X+12-12=0-12 x =11 x= -12 Check x +x²= 132 x +x²= 132 -12 +-12²= 132 11 +11²= 132 -12 + 144 = 132 11+ 121=132 132= 132 132=132 Since the problem says positive the answer is (11,121)

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