wantza03
24

use pythagorena theorme D=$\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}$ NOTE: x1 and x2 means the first x and second x, not x^1 and x^2 points given are (1,1) (5,6) x1=1 y1=1 x2=5 y2=6 D=$\sqrt{(1-5)^{2}+(1-6)^{2}}$ D=$\sqrt{(-4)^{2}+(-5)^{2}}$ D=$\sqrt{16+25}$ D=$\sqrt{41}$ 6.403 answer is B
Use the distance formula to find the distance between two points. D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$ The points are (5, 6) and (1, 1) D= $\sqrt{(5-1)^2+(6-1)^2}$ D= $\sqrt{4^2+5^2}$ D= $\sqrt{16+25}$ D= $\sqrt{41}$ $\sqrt{41}$ is about 6.4 B. 6.4 units Hope this helps :)