Mathematics
xXMrDuckXx
10

Solve 4x to the second power Minus 9

+1
(2) Answers
sabiraami25

[latex]4x^2-9[/latex]Here I have included 3 methods: Differentiating, Integrating and factorizeDifferentiating: [latex]4x^2-9[/latex][latex]2*4x^2^-^1[/latex][latex]8x^2^-^1[/latex][latex]= 8x[/latex]Integrating: [latex] \int\limits 4x^2-9dx[/latex][latex] \frac{4x^3}{3}-9x+C [/latex]Factorise: [latex](2x-3)(2x+3)[/latex] 

monicabaugh

2so 4x^2-9 is obviously the difference of 2 perfect squares so (a)^2-(b)^2 can be factored into (a-b)(a+b) so 4x^2-9=(2x)^2-(3)^2 which is (2x-3)(2x+3)

Add answer