Mathematics
hdaisy040
15

Solve 8m² + 20m = 12 for m by factoring Please show all work

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vane12

[latex]8m^{2}+20m=12 / :2[/latex] [latex]4m^{2}+10m=6[/latex] [latex]4m^{2}+10m-6 =0[/latex] [latex]\Delta=b^{2}-4ac[/latex] [latex]\Delta=100-(4*4*-6)[/latex] [latex]\Delta=100+96=196[/latex] [latex]x1=\frac{-b-\sqrt{\Delta}}{8}[/latex] [latex]x1=\frac{-10-14}{8}[/latex] [latex]x1=\frac{-24}{8}[/latex] [latex]x1=-3[/latex] [latex]x1=\frac{-b+\sqrt{\Delta}}{8}[/latex] [latex]x2=\frac{-10+14}{8}[/latex] [latex]x2=\frac{1}{2}[/latex] so you can write [latex]8m^{2}+20m=12 / :2[/latex] as [latex]8(m+3)(m-\frac{1}{2})=8*[m^{2}+2.5m-1.5]=0[/latex]

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