hdaisy040
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# Solve 8m² + 20m = 12 for m by factoring Please show all work

$8m^{2}+20m=12 / :2$ $4m^{2}+10m=6$ $4m^{2}+10m-6 =0$ $\Delta=b^{2}-4ac$ $\Delta=100-(4*4*-6)$ $\Delta=100+96=196$ $x1=\frac{-b-\sqrt{\Delta}}{8}$ $x1=\frac{-10-14}{8}$ $x1=\frac{-24}{8}$ $x1=-3$ $x1=\frac{-b+\sqrt{\Delta}}{8}$ $x2=\frac{-10+14}{8}$ $x2=\frac{1}{2}$ so you can write $8m^{2}+20m=12 / :2$ as $8(m+3)(m-\frac{1}{2})=8*[m^{2}+2.5m-1.5]=0$