msbeauty
16

# Solve for x and y. 4x-3y=16 -2x+4y=-2 DUE 2/7/17!

$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$ Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together. $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$ $\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$ -------------------- $5y = 12$ $\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$ Let's replace the value found in the first equation: $4x-3y=16\:(I)$ $4x-3*( \frac{12}{5}) =16$ $4x - \frac{36}{5} = 16$ least common multiple (5) $\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$ $20x - 36 = 80$ $20x = 80 + 36$ $20x = 116$ $x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark$