solve the system of equations algebraically x+6y=20 and 5x-3y=34

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(1) Answers

jenii13

x+6y = 20 (1)
5x-3y = 34 (2)
multiply (2) by 2 to get (3)
10x-6y = 68 (3)
add (1) and (3) together, the y cancels out
11x = 88
x = 8
substitute x=8 into (1) or (2) to find y
8+6y = 20
6y = 12
y = 2
x=8 y=2