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# Solve this inequality: 3p – 16 < Solve this inequality: 3p – 16 < 20

3p - 16 < 20 Take 16 to the right side 3p - 16 + (16) < 20 + (16) -16 and +16 cancels out 3p < 36 Divide by 3 on both sides to isolate p $\frac{3p}{3}$ < $\frac{36}{3}$ 3 and 3 cancels out p < 12 The value of p will be less than 12, not 12 itself, or more Try plugging in 12: 3(12) - 16 < 20 36 - 16 < 20 20 < 20    x 20 is not greater than 20  So, only the values less than 12 will be applicable.