Mathematics
mikennajadewege
3

Someone please help me? I don't know how to solve these :/

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(2) Answers
shaun1

[latex]2x^2 - x - 6 = 0[/latex] [latex](2x - 3) (x + 2) = 0[/latex] [latex]2x - 3 = 0[/latex] [latex]2x = 3[/latex] [latex]x = \frac{3}{2} [/latex] [latex]x + 2 = 0[/latex] [latex]x = -2[/latex] [latex]x = \frac{3}{2} , 2[/latex]

yassautumn

[latex]2x^2-x-6=0\\ 2x^2-4x+3x-6=0\\ 2x(x-2)+3(x-2)=0\\ (2x+3)(x-2)=0\\ x=-\frac{3}{2} \vee x=2[/latex]

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