Mathematics
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The area of a rectangle is 84 square inches. the length of the rectangle is 2 longer than twice the width. find the width and the perimeter of the triangle

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nelly400

Let l = the lentth of the rectangle and w = the width of the rectangle; where w>0 and l>0; We have 84 = l x w and l = 2 + w; 84 = (2+w) x w; We solve the equation: w^2 + 2w - 84 = 0; We obtain the solution w = 8.21; The perimeter of the triangle is  is 3 x 8.21 = 24.63;

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