The function y = x2 is transformed to y = (x + 4)2. Which statement is true about the transformed function? It is an even function. It is an odd function. It is neither an even nor an odd function. It is both an even and an odd function.

Even function: f(-x) = f(x). If you replace x by -x you should find the same function. Odd function: f(-x) = -f(x). If you replace x by -x you  find the same function with opposite sign; Is f(-x) = f(x)? f(x) = (x+4)² =  x² + 8x +16 f(-x) = (-x+4)² = x² - 8x + 16, then it's not an even function Is f(-x) = -f(x)? f(-x) = (-x+4)² = x² + 8x + 16 , then it's not an odd function It is neither an even nor an odd function