Mathematics
4fasad
8

The length of a rectangle is twice its width. The perimeter is 60 ft. Find its area. A = 10 ft2 A = 100 ft2 A = 200 ft2

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(2) Answers
jiggyasom

The answer is 200 ft2

Westfall216

To find of the area, we do the following: Declare variables we will use: Let 'x' be the length of width Create equation using information we have: Width's length is equal to 2x because a rectangle has two width Length's length is equal to 4x because we know that the length of the rectangle is twice its width. So that is 2x. Since there is two length of a rectangle, its 2x * 2 = 4x. The equation is 4x + 2x = 60 feet 6x = 60 Find the x to find perimeter and area: 6x = 60 Divide both side by 6 x = 10 Width = 10 feet Perimeter = 2x = 2(10) = 20 feet Area = 10 * 20 = 200 feet² Therefore, the answer is 200 feet².

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