The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is

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Think of it this way. First we can use all 6 digits to start with, right? But after that we can only have 5 digits, then four, right? And it stops there because we can only have 3 digits. So we multiply 6 * 5 * 3 to get 90. So there are 90 combinations.  IF this helped please rate, thank, and give brainliest answer!

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