jhiemmyluthfi99
12

# the question says evaluate 2a-b/b when a=4 and b=-3. How would I start this problem?

$\frac{2a-b}{b}\\\\substitute\ a=4;\ b=-3:\\\\\frac{2\cdot4-(-3)}{-3}=\frac{8+3}{-3}=-\frac{11}{3}=-3\frac{2}{3}$ $or\ if\ 2a+\frac{b}{b}=2a+1\ then\ for\ a=4\ and\ b=-3:\\\\2\cdot4-3=8-3=5$