the sum of three numbers is 45. the second of the three numbers is three more than twice the first number, x. the third number is two more than the first number, x. which equation can be used to solve for the first number, x?

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your equation is x + (3+2x) + (2+x) = 45 x being the first number, (3+2x) being the second, and (2+x) being the third. not sure if i was supposed to try to simplify. hope this helps!!

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