Tickets to a show cost $10 in advance and $15 at the door. If 120 tickets are sold for a total of $1,390, how many of the tickets were bought in advance?

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(1) Answers

longhornlova12

Let x = number of tickets bought in advance
y = number of tickets bought at the door
We have two unknowns therefore we need to equations to solve the problem. We do as follows:
x + y = 120
10x + 15y = 1390
SOlving simultaneously,
x = 82
y = 38