Twice the diffrence of a number and 9 is equal to three times the sum of the number and 5. Find the number
(1) Answers
2(n-9) = 3(n + 5) 2n - 18 = 3n + 15 2n - 3n = 15 + 18 -n = 33 n = -33
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2(n-9) = 3(n + 5) 2n - 18 = 3n + 15 2n - 3n = 15 + 18 -n = 33 n = -33