Mathematics
kirakj
1

use substitution to solve the sytem: 5x-3y=-20 and x=3y-16

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(2) Answers
kendallmachinski

5(3y-16)-3y = -20 15y-80-3y = -20 12y = 60 y = 5

monsterman2014

[latex] 5x - 3y = -20 [/latex] [latex] x = 3y - 16 [/latex] Plug in 'x' into the first equation: [latex] 5 (3y - 16) - 3y = 20 [/latex] [latex] 15y - 80 - 3y = -20 [/latex] [latex] 12y = 60 [/latex] [latex] y = 5 [/latex]  Plug in 'y' into the second equation to get 'x': [latex] x = 3y - 16 [/latex] [latex] x = 3(5) - 16 [/latex] To get [latex] x = -1 [/latex] [latex] y = 5 [/latex] [latex] x = -1 [/latex]

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