mta3
17

What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

$x^{2}-3x-5=0 \\ \\ \Delta=(-3)^{2}-4*1*(-5)=9+20=29 \\ \\ \sqrt{\Delta} = \sqrt{29} \\ \\ x_{1}= \frac{3- \sqrt{29} }{2} \\ \\ x_{2}= \frac{3+ \sqrt{29} }{2}$ \\\ Ben