Mathematics
taylorhartke
2

What are the possible values for x in the equation 4x^2 = 64 (1) x=0        (2) x=4       (3) x=4,-4      (4) x=0,4,-4

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(2) Answers
shaun1

4x^2 = 64 1) 4(0^2) = 64 4(0) = 64 0 = 64 Not True 2) 4(4^2) = 64 4(16) = 64 64 = 64 True 3) 4(4^2) = 64 4(16) = 64 64 = 64 4(-4^2) = 64 4(16) = 64 64 = 64 True 4) 4(4^2) = 64 4(16) = 64 64 = 64 4(-4^2) = 64 4(16) = 64 64 = 64 4(0^2) = 64 4(0) = 64 0 = 64 Not True Answer: (3)

Gracie216

[latex]4x^2 = 64\ \ /:4 \\ \\x^2=16 \\ \\ x^2-16=0 \\ \\x^2-4^2=0\\ \\ (x-4)(x+4)=0\\ \\x-4=0 \ \ or \ \ x+4=0 \\ \\ x=4 \ \ or \ \ x= -4 \\ \\ Answer : \ (3) [/latex]

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