Mathematics
Alina2
5

what is the area of a sector with radius 4 and an angle of 18°?

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(1) Answers
Llama11

Area of a circle =  πr² But area of a sector = (θ/360°) * πr² θ = 18°,  radius, r = 4 Area of sector = (18°/360°) * π*4² = (18°/360°) * π*4*4                                                          =  1/20*π*4*4              18 into 360 is 20                                                           = 4π / 5 = 0.8π Using π as ≈ 3.142,    A = 0.8π ≈ 0.8 * 3.142 ≈ 2.5163 Area of sector = 0.8π ≈ 2.5136 square units.

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